Subjects algebra

Solve Linear Equation 8Cb12F

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1. **State the problem:** Solve the equation $$\frac{2}{3}w - \frac{2}{3} = 0$$ for $w$. 2. **Write down the equation:** $$\frac{2}{3}w - \frac{2}{3} = 0$$ 3. **Add $\frac{2}{3}$ to both sides to isolate the term with $w$: $$\frac{2}{3}w - \frac{2}{3} + \frac{2}{3} = 0 + \frac{2}{3}$$** 4. **Simplify:** $$\frac{2}{3}w = \frac{2}{3}$$ 5. **Divide both sides by $\frac{2}{3}$ to solve for $w$: $$w = \frac{\frac{2}{3}}{\frac{2}{3}}$$** 6. **Use the cancellation rule:** $$w = \frac{\cancel{\frac{2}{3}}}{\cancel{\frac{2}{3}}} = 1$$ 7. **Final answer:** $$w = 1$$ This means the value of $w$ that satisfies the equation is 1.