1. The problem is to solve the equation $$\frac{2x+3}{4} = 5$$ for $x$. 2. The formula used here is to isolate $x$ by eliminating the denominator and then solving the resulting linear equation. 3. Multiply both sides of the equation by 4 to cancel the denominator: $$4 \times \frac{2x+3}{4} = 4 \times 5$$ which simplifies to $$\cancel{4} \times \frac{2x+3}{\cancel{4}} = 20$$ so $$2x + 3 = 20$$ 4. Subtract 3 from both sides to isolate the term with $x$: $$2x + 3 - 3 = 20 - 3$$ which simplifies to $$2x = 17$$ 5. Divide both sides by 2 to solve for $x$: $$\frac{2x}{2} = \frac{17}{2}$$ which simplifies to $$\cancel{2}x / \cancel{2} = \frac{17}{2}$$ so $$x = \frac{17}{2}$$ 6. The solution is $x = \frac{17}{2}$ or $8.5$. This means that when $x$ is $8.5$, the original equation holds true.