Subjects algebra

Solve Linear Equation B56489

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1. **State the problem:** Solve the equation $8r - 12 = -28$ using the bar method. 2. **Understand the equation:** The equation means that when you take $8$ times a number $r$ and subtract $12$, the result is $-28$. 3. **Set up the bar model:** Imagine a bar divided into 8 equal parts representing $8r$. From this bar, subtract 12 units to get $-28$. 4. **Isolate the term with $r$:** Add 12 to both sides to move the constant term. $$8r - 12 + 12 = -28 + 12$$ $$8r = -16$$ 5. **Divide both sides by 8 to solve for $r$:** $$\frac{\cancel{8}r}{\cancel{8}} = \frac{-16}{8}$$ 6. **Simplify the right side:** $$r = -2$$ 7. **Final answer:** The value of $r$ that satisfies the equation is $r = -2$. This means if you multiply $-2$ by 8 and subtract 12, you get $-28$.