Subjects algebra

Solve Linear Equation Be9980

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1. **State the problem:** Solve the equation $\frac{3}{2}X - 3 = 3$ for $X$. 2. **Add 3 to both sides** to isolate the term with $X$: $$\frac{3}{2}X - 3 + 3 = 3 + 3$$ which simplifies to $$\frac{3}{2}X = 6$$ 3. **Divide both sides by $\frac{3}{2}$** to solve for $X$: $$X = \frac{6}{\frac{3}{2}}$$ Use the rule that dividing by a fraction is the same as multiplying by its reciprocal: $$X = 6 \times \frac{2}{3}$$ 4. **Simplify the multiplication:** $$X = \cancel{6} \times \frac{2}{3} = \cancel{6} \times \frac{2}{3} = 2 \times 2 = 4$$ 5. **Final answer:** $$X = 4$$ This means the value of $X$ that satisfies the equation is 4.