1. The problem is to solve for $x$ in the equation $\frac{2x+3}{4} = 5$. 2. We use the property of equality that if $\frac{a}{b} = c$, then $a = bc$. 3. Multiply both sides by 4 to eliminate the denominator: $$\cancel{4} \times \frac{2x+3}{\cancel{4}} = 5 \times 4$$ which simplifies to $$2x + 3 = 20$$ 4. Subtract 3 from both sides to isolate the term with $x$: $$2x + 3 - 3 = 20 - 3$$ $$2x = 17$$ 5. Divide both sides by 2 to solve for $x$: $$\frac{\cancel{2}x}{\cancel{2}} = \frac{17}{2}$$ $$x = \frac{17}{2}$$ 6. The solution is $x = \frac{17}{2}$ or $8.5$. This means when $x$ is $8.5$, the original equation holds true.