1. **State the problem:** Solve the system of linear equations: $$14p + 4s = 128$$ $$6p + 2s = 60$$ 2. **Formula and rules:** We can solve this system using the elimination or substitution method. Here, we'll use elimination to eliminate one variable. 3. **Eliminate variable $s$:** Multiply the second equation by 2 to match the coefficient of $s$ in the first equation: $$2 \times (6p + 2s) = 2 \times 60$$ $$12p + 4s = 120$$ 4. **Subtract the new second equation from the first:** $$14p + 4s - (12p + 4s) = 128 - 120$$ $$\cancel{14p} + \cancel{4s} - \cancel{12p} - \cancel{4s} = 8$$ $$2p = 8$$ 5. **Solve for $p$:** $$p = \frac{8}{2} = 4$$ 6. **Substitute $p=4$ into the second original equation:** $$6(4) + 2s = 60$$ $$24 + 2s = 60$$ 7. **Solve for $s$:** $$2s = 60 - 24 = 36$$ $$s = \frac{36}{2} = 18$$ **Final answer:** $$p = 4, \quad s = 18$$