1. **State the problem:** Solve the system of linear equations:
$$\begin{cases} x + y = -3 \\ x - y = 11 \end{cases}$$
2. **Formula and rules:** To solve a system of two linear equations, we can use the method of addition (elimination) or substitution. Here, addition is convenient because adding the two equations will eliminate $y$.
3. **Add the two equations:**
$$ (x + y) + (x - y) = -3 + 11 $$
Simplify:
$$ x + y + x - y = 8 $$
$$ 2x = 8 $$
4. **Divide both sides by 2:**
$$ \cancel{2}x = \cancel{2}4 $$
$$ x = 4 $$
5. **Substitute $x=4$ into the first equation:**
$$ 4 + y = -3 $$
6. **Solve for $y$:**
$$ y = -3 - 4 $$
$$ y = -7 $$
7. **Final answer:**
$$ x = 4, \quad y = -7 $$
This means the two lines intersect at the point $(4, -7)$.
Solve Linear System 42009A
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