1. **State the problem:** Solve the system of equations:
$$x + y = 5$$
$$x - y = 1$$
2. **Formula and rules:** To solve a system of linear equations, we can use the addition (elimination) method or substitution method. Here, we use addition to eliminate one variable.
3. **Add the two equations:**
$$\begin{aligned} (x + y) + (x - y) &= 5 + 1 \\ x + y + x - y &= 6 \\ 2x &= 6 \end{aligned}$$
4. **Simplify and solve for $x$:**
$$x = \frac{6}{2}$$
$$x = 3$$
5. **Substitute $x=3$ into the first equation to find $y$:**
$$3 + y = 5$$
$$y = 5 - 3$$
$$y = 2$$
6. **Final answer:**
$$x = 3, \quad y = 2$$
This means the solution to the system is the point $(3, 2)$ where both equations intersect.
Solve Linear System 64Acc8
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