1. **State the problem:** Solve the system of equations:
$$A + B = 2$$
$$2A + B = 1$$
2. **Use substitution or elimination method:** Here, we use elimination.
3. **Subtract the first equation from the second:**
$$\cancel{2A + B} - \cancel{(A + B)} = 1 - 2$$
$$2A + B - A - B = -1$$
$$A = -1$$
4. **Substitute $A = -1$ into the first equation:**
$$-1 + B = 2$$
5. **Solve for $B$:**
$$B = 2 + 1 = 3$$
6. **Final answer:**
$$A = -1, \quad B = 3$$
Solve Linear System Abb0Ea
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