1. **State the problem:** We are given two equations: $$x = -2$$ $$3y + 2x = 5$$ We need to find the value of $y$. 2. **Use substitution:** Since $x$ is already given as $-2$, substitute $x = -2$ into the second equation: $$3y + 2(-2) = 5$$ 3. **Simplify the equation:** $$3y - 4 = 5$$ 4. **Isolate $y$:** Add 4 to both sides: $$3y - 4 + 4 = 5 + 4$$ $$3y = 9$$ 5. **Solve for $y$:** Divide both sides by 3: $$\frac{\cancel{3}y}{\cancel{3}} = \frac{9}{3}$$ $$y = 3$$ **Final answer:** $$y = 3$$