1. **State the problem:** We are given two equations:
$$\frac{x}{y} = 4$$
and
$$x - y = 6$$
We need to find the value of $x + y$.
2. **Use the first equation to express $x$ in terms of $y$:**
$$x = 4y$$
3. **Substitute $x = 4y$ into the second equation:**
$$4y - y = 6$$
4. **Simplify the left side:**
$$3y = 6$$
5. **Solve for $y$:**
$$y = \frac{6}{3}$$
Show cancellation:
$$y = \frac{\cancel{6}}{\cancel{3}} = 2$$
6. **Find $x$ using $x = 4y$:**
$$x = 4 \times 2 = 8$$
7. **Calculate $x + y$:**
$$x + y = 8 + 2 = 10$$
**Final answer:**
$$\boxed{10}$$
Solve Linear System E9Bab4
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