1. The problem is to solve the equation involving two special operators $\oplus$ and $\boxplus$ and an unknown $\square$: $$5 \oplus 1 \boxplus \square = 3$$ 2. Since the operators $\oplus$ and $\boxplus$ are not standard, we need to define or assume their meaning. Without additional information, we can treat them as placeholders for operations or treat the problem as finding $\square$ such that the equation holds. 3. Let's assume $\oplus$ and $\boxplus$ represent addition for simplicity (common in puzzles). Then the equation becomes: $$5 + 1 + \square = 3$$ 4. Simplify the left side: $$6 + \square = 3$$ 5. To isolate $\square$, subtract 6 from both sides: $$\cancel{6} + \square = 3 - \cancel{6}$$ $$\square = 3 - 6$$ 6. Calculate the right side: $$\square = -3$$ 7. Therefore, the value of $\square$ that satisfies the equation is $-3$.