1. **State the problem:** Solve the polynomial equation $$(5x - 2)^3 + 28 = 0$$ algebraically for the exact value of $x$.
2. **Rewrite the equation:** Move 28 to the right side:
$$ (5x - 2)^3 = -28 $$
3. **Take the cube root of both sides:**
$$ 5x - 2 = \sqrt[3]{-28} $$
4. **Isolate $x$:**
$$ 5x = 2 + \sqrt[3]{-28} $$
5. **Divide both sides by 5:**
$$ x = \frac{2 + \sqrt[3]{-28}}{5} $$
6. **Check the options:** The correct exact solution matches
$$ x = \frac{2 + \sqrt[3]{-28}}{5} $$
**Final answer:**
$$ x = \frac{2 + \sqrt[3]{-28}}{5} $$
Solve Polynomial Decdcb
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