1. **State the problem:** Solve the equation $$\frac{6 + 2}{x} \times 3 = \frac{8}{x}$$ for $x$. 2. **Simplify the numerator:** Calculate $6 + 2$. $$6 + 2 = 8$$ So the equation becomes: $$\frac{8}{x} \times 3 = \frac{8}{x}$$ 3. **Rewrite the equation:** Multiply the left side numerator by 3: $$\frac{8 \times 3}{x} = \frac{8}{x}$$ which is $$\frac{24}{x} = \frac{8}{x}$$ 4. **Important rule:** When two fractions with the same denominator are equal, their numerators must be equal (assuming $x \neq 0$). 5. **Set numerators equal:** $$24 = 8$$ This is false, so no solution exists if $x \neq 0$. 6. **Check if $x=0$ is possible:** Since $x$ is in the denominator, $x=0$ is not allowed. **Conclusion:** There is no value of $x$ that satisfies the equation. **First step summary:** Simplify $6 + 2$ to get $8$ and rewrite the equation as $$\frac{8}{x} \times 3 = \frac{8}{x}$$.