1. **State the problem:** Solve the equation $4x^2 = 28$ and write the solutions using ± notation. 2. **Write the formula and rules:** To solve for $x$ when you have an equation of the form $ax^2 = b$, divide both sides by $a$ and then take the square root of both sides. Remember, taking the square root gives two solutions: positive and negative. 3. **Divide both sides by 4:** $$x^2 = \frac{28}{4}$$ Show cancelation: $$x^2 = \frac{\cancel{28}}{\cancel{4}} = 7$$ 4. **Take the square root of both sides:** $$x = \pm \sqrt{7}$$ 5. **Final answer:** $$x = \pm \sqrt{7}$$ This means $x$ can be either positive or negative square root of 7.