1. **State the problem:** Solve the quadratic equation $ (x-6)(x+3) = 0 $. 2. **Use the zero product property:** If the product of two factors is zero, then at least one of the factors must be zero. So, set each factor equal to zero: $$ x - 6 = 0 \quad \text{or} \quad x + 3 = 0 $$ 3. **Solve each equation:** - For $x - 6 = 0$, add 6 to both sides: $$ x = 6 $$ - For $x + 3 = 0$, subtract 3 from both sides: $$ x = -3 $$ 4. **Final answer:** The solutions to the quadratic equation are $$ x = 6 \quad \text{or} \quad x = -3 $$