1. The problem is to solve the equation $x^2 + 12 = 76$ for $x$.
2. The formula used here is to isolate $x^2$ by subtracting 12 from both sides:
$$x^2 + 12 - 12 = 76 - 12$$
3. Simplify both sides:
$$x^2 = 64$$
4. To solve for $x$, take the square root of both sides:
$$x = \pm \sqrt{64}$$
5. Calculate the square root:
$$x = \pm 8$$
6. Therefore, the solutions are:
$$x = 8 \text{ or } x = -8$$
This means $x$ can be either 8 or -8 to satisfy the equation.
Solve Quadratic 174461
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