1. **State the problem:** Solve the equation $2y^2(4-2) = 16$ for $y$. 2. **Simplify the expression inside the parentheses:** $$4 - 2 = 2$$ So the equation becomes: $$2y^2 \times 2 = 16$$ 3. **Multiply the constants:** $$2 \times 2 = 4$$ So: $$4y^2 = 16$$ 4. **Isolate $y^2$ by dividing both sides by 4:** $$\frac{\cancel{4}y^2}{\cancel{4}} = \frac{16}{4}$$ $$y^2 = 4$$ 5. **Take the square root of both sides:** $$y = \pm \sqrt{4}$$ $$y = \pm 2$$ **Final answer:** $$y = 2 \text{ or } y = -2$$