1. **State the problem:** Find the two solutions to the equation $$(3x - 1)(x - 5) = 0$$.
2. **Formula and rule:** The zero product property states that if a product of two factors equals zero, then at least one of the factors must be zero. So, we set each factor equal to zero:
$$3x - 1 = 0$$
$$x - 5 = 0$$
3. **Solve the first equation:**
$$3x - 1 = 0$$
Add 1 to both sides:
$$3x = 1$$
Divide both sides by 3:
$$x = \frac{\cancel{3}x}{\cancel{3}} = \frac{1}{3}$$
4. **Solve the second equation:**
$$x - 5 = 0$$
Add 5 to both sides:
$$x = 5$$
5. **Final answer:** The two solutions are
$$x = \frac{1}{3} \quad \text{and} \quad x = 5$$.
Solve Quadratic 2558D9
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