1. **State the problem:** Solve the equation $ (3x - 8)(4x - 5) = 0 $ for $x$.
2. **Formula and rule:** The zero product property states that if a product of two factors equals zero, then at least one of the factors must be zero. So, set each factor equal to zero:
$$ 3x - 8 = 0 \quad \text{or} \quad 4x - 5 = 0 $$
3. **Solve the first equation:**
$$ 3x - 8 = 0 $$
Add 8 to both sides:
$$ 3x = 8 $$
Divide both sides by 3:
$$ x = \frac{\cancel{3}x}{\cancel{3}} = \frac{8}{3} $$
4. **Solve the second equation:**
$$ 4x - 5 = 0 $$
Add 5 to both sides:
$$ 4x = 5 $$
Divide both sides by 4:
$$ x = \frac{\cancel{4}x}{\cancel{4}} = \frac{5}{4} $$
5. **Final answer:** The solutions to the equation are
$$ x = \frac{8}{3} \quad \text{or} \quad x = \frac{5}{4} $$
Solve Quadratic 294003
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