1. **State the problem:** Simplify the expression and solve the equation:
$$m - 1 + 2\sqrt{m} + 4 + m - 1 = 1$$
2. **Combine like terms:** Group the terms involving $m$ and constants:
$$m + m - 1 - 1 + 4 + 2\sqrt{m} = 1$$
Simplify the constants:
$$2m + 2 + 2\sqrt{m} = 1$$
3. **Isolate terms:** Move constants to the right side:
$$2m + 2\sqrt{m} = 1 - 2$$
$$2m + 2\sqrt{m} = -1$$
4. **Divide entire equation by 2:**
$$m + \sqrt{m} = -\frac{1}{2}$$
5. **Analyze the equation:** Since $m$ and $\sqrt{m}$ are real numbers, and $\sqrt{m}$ is defined only for $m \geq 0$, the left side is always non-negative or zero, but the right side is negative.
6. **Conclusion:** There is no real solution to the equation because the left side cannot be negative while the right side is $-\frac{1}{2}$.
**Final answer:** No real solution exists for the given equation.
Solve Radical Equation B3E3A7
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