1. **State the problem:** Solve the equation $$\frac{6}{3} = \frac{V + 11}{3V - 12}$$ for $V$.
2. **Simplify the left side:** $$\frac{6}{3} = 2$$, so the equation becomes $$2 = \frac{V + 11}{3V - 12}$$.
3. **Use cross multiplication:** Multiply both sides by $3V - 12$ to eliminate the denominator:
$$2(3V - 12) = V + 11$$.
4. **Expand the left side:**
$$6V - 24 = V + 11$$.
5. **Bring all terms involving $V$ to one side and constants to the other:**
$$6V - V = 11 + 24$$
$$5V = 35$$.
6. **Divide both sides by 5 to solve for $V$:**
$$\frac{\cancel{5}V}{\cancel{5}} = \frac{35}{5}$$
$$V = 7$$.
**Final answer:** $$V = 7$$.
Solve Rational 1Dc3C0
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.