1. We are asked to solve the equation $$\frac{x - 2}{x + 3} = 0$$ for $x$. 2. Recall that a fraction equals zero if and only if its numerator is zero and the denominator is not zero. 3. Set the numerator equal to zero: $$x - 2 = 0$$ 4. Solve for $x$: $$x = 2$$ 5. Check the denominator to ensure it is not zero at $x=2$: $$2 + 3 = 5 \neq 0$$ 6. Since the denominator is not zero, $x=2$ is a valid solution. Final answer: $$x = 2$$