1. **State the problem:** We need to solve the equation $$\frac{2x+4}{x-3} = 3$$ for $x$. 2. **Recall the formula and rules:** To solve rational equations, multiply both sides by the denominator to eliminate the fraction, but remember to check for values that make the denominator zero (excluded values). 3. **Identify excluded values:** The denominator $x-3$ cannot be zero, so $x \neq 3$. 4. **Multiply both sides by $x-3$ to clear the fraction:** $$\cancel{\frac{2x+4}{x-3}} \times (x-3) = 3 \times (x-3)$$ which simplifies to $$2x + 4 = 3(x - 3)$$ 5. **Expand the right side:** $$2x + 4 = 3x - 9$$ 6. **Bring all terms to one side to isolate $x$:** $$2x + 4 - 3x + 9 = 0$$ which simplifies to $$-x + 13 = 0$$ 7. **Solve for $x$:** $$-x = -13$$ $$x = 13$$ 8. **Check the solution against excluded values:** Since $x=13$ is not equal to $3$, it is valid. **Final answer:** $$x = 13$$