1. The problem is to solve the system of equations: $$\begin{cases} x + 2y = 6 \\ x = -2 \end{cases}$$ 2. We use substitution since $x$ is already isolated in the second equation: $x = -2$. 3. Substitute $x = -2$ into the first equation: $$-2 + 2y = 6$$ 4. Solve for $y$: $$2y = 6 - (-2)$$ $$2y = 6 + 2$$ $$2y = 8$$ 5. Divide both sides by 2: $$y = \frac{\cancel{2}y}{\cancel{2}} = \frac{8}{2}$$ $$y = 4$$ 6. The solution to the system is: $$x = -2, \quad y = 4$$ This means the point $(-2,4)$ satisfies both equations.