1. The problem is to find the solution $(x,y)$ to the system of equations: $$y = 12x - 20$$ $$y = 28$$ 2. Since $y=28$, substitute $y$ in the first equation: $$28 = 12x - 20$$ 3. Add 20 to both sides: $$28 + 20 = 12x - 20 + 20$$ $$48 = 12x$$ 4. Divide both sides by 12: $$\frac{48}{\cancel{12}} = \frac{12x}{\cancel{12}}$$ $$4 = x$$ 5. So the solution is: $$(x,y) = (4, 28)$$ 6. Checking the options, the correct answer is A. (4, 28).