1. **State the problem:** Solve the system of linear equations: $$\begin{cases} 3x + 2y = -9 \\ x - 2y = -3 \end{cases}$$ 2. **Use substitution or elimination method.** Here, we use substitution from the second equation: $$x - 2y = -3 \implies x = -3 + 2y$$ 3. **Substitute $x$ into the first equation:** $$3(-3 + 2y) + 2y = -9$$ 4. **Simplify and solve for $y$:** $$-9 + 6y + 2y = -9$$ $$8y - 9 = -9$$ $$8y = -9 + 9$$ $$8y = 0$$ $$y = \frac{0}{8}$$ $$y = 0$$ 5. **Substitute $y=0$ back into $x = -3 + 2y$ to find $x$:** $$x = -3 + 2(0)$$ $$x = -3$$ 6. **Final solution:** $$x = -3, \quad y = 0$$