1. **State the problem:** Solve the system of equations by graphing:
$$y = -2x + 8$$
$$y = x + 5$$
2. **Understand the problem:** We want to find the point(s) where the two lines intersect. This point satisfies both equations simultaneously.
3. **Set the equations equal to each other:** Since both equal $y$, set the right sides equal:
$$-2x + 8 = x + 5$$
4. **Solve for $x$:**
$$-2x + 8 = x + 5$$
Add $2x$ to both sides:
$$\cancel{-2x} + 8 + 2x = x + 5 + 2x$$
$$8 = 3x + 5$$
Subtract 5 from both sides:
$$8 - 5 = 3x + \cancel{5} - 5$$
$$3 = 3x$$
Divide both sides by 3:
$$\frac{3}{\cancel{3}} = \frac{3x}{\cancel{3}}$$
$$1 = x$$
5. **Find $y$ by substituting $x=1$ into one of the original equations:**
Using $y = x + 5$:
$$y = 1 + 5 = 6$$
6. **Solution:** The lines intersect at the point $(1, 6)$.
This means the solution to the system is:
$$\boxed{(1, 6)}$$
Solve System Babf09
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