1. The problem asks to solve for $x$ when $x=9.6$. Since $x$ is already given as 9.6, the solution is simply: $$x=9.6$$ 2. The problem asks to solve for $x$ when $x=178$. Similarly, $x$ is already given as 178, so the solution is: $$x=178$$ 3. The problem asks to find the value of $x$ in simplest radical form based on the geometric figure described. Given the description of a circle with a chord of length 11 and a tangent segment of length 10 intersecting outside the circle, forming a right triangle with one leg 9 and hypotenuse $x$. We use the Pythagorean theorem for the right triangle: $$x^2 = 9^2 + 11^2$$ Calculate the squares: $$x^2 = 81 + 121 = 202$$ Take the square root: $$x = \sqrt{202}$$ Simplify the radical if possible. Since 202 = 2 * 101 and 101 is prime, it cannot be simplified further. Therefore, the simplest radical form is: $$x = \sqrt{202}$$