1. Let's start by stating the problem: solving radicals means simplifying expressions that contain roots, such as square roots, cube roots, etc.
2. There are different types of radicals to consider:
- Simple radicals like $\sqrt{a}$
- Radicals with denominators like $\frac{1}{\sqrt{b}}$
- Radicals with radical denominators like $\frac{1}{\sqrt{c}}$
3. Important rules:
- $\sqrt{a} \times \sqrt{b} = \sqrt{ab}$
- To simplify radicals, factor the number inside the root into perfect squares.
- To rationalize denominators, multiply numerator and denominator by the radical in the denominator.
4. Example 1: Simplify $\sqrt{50}$
- Factor 50 as $25 \times 2$
- $\sqrt{50} = \sqrt{25 \times 2} = \sqrt{25} \times \sqrt{2} = 5\sqrt{2}$
5. Example 2: Simplify $\frac{1}{\sqrt{3}}$
- Multiply numerator and denominator by $\sqrt{3}$ to rationalize denominator:
- $\frac{1}{\sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{\cancel{\sqrt{3}} \times \cancel{\sqrt{3}}} = \frac{\sqrt{3}}{3}$
6. Example 3: Simplify $\frac{5}{\sqrt{2} + 1}$
- Multiply numerator and denominator by the conjugate $\sqrt{2} - 1$:
- $\frac{5}{\sqrt{2} + 1} \times \frac{\sqrt{2} - 1}{\sqrt{2} - 1} = \frac{5(\sqrt{2} - 1)}{(\sqrt{2} + 1)(\sqrt{2} - 1)}$
- Denominator simplifies using difference of squares:
- $(\sqrt{2})^2 - 1^2 = 2 - 1 = 1$
- So expression becomes $5(\sqrt{2} - 1) = 5\sqrt{2} - 5$
7. Summary:
- Simplify radicals by factoring inside the root.
- Rationalize denominators by multiplying numerator and denominator by the radical or conjugate.
Final answers:
- $\sqrt{50} = 5\sqrt{2}$
- $\frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3}$
- $\frac{5}{\sqrt{2} + 1} = 5\sqrt{2} - 5$
Solving Radicals 6Cf5B3
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