Subjects algebra

Speed Stopping Distance 9Aa15A

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1. **State the problem:** We have a function represented by a table with Speed (mi/hr) as the independent variable and Stopping Distance (ft) as the dependent variable. We need to identify variables, domain, range, and describe the function. 2. **Identify variables:** The independent variable is Speed ($x$), and the dependent variable is Stopping Distance ($y$). 3. **Domain:** The domain is the set of all input values for Speed. From the table, the minimum speed is 10 and the maximum speed is 70. So, the domain is $\{10, 20, 30, 40, 50, 60, 70\}$. 4. **Range:** The range is the set of all output values for Stopping Distance. From the table, the values are $\{16, 43, 74, 117, 169, 223, 307\}$. 5. **Describe the function:** As speed increases, the stopping distance increases. The relationship is not linear; the stopping distance grows faster as speed increases, indicating a nonlinear function, likely quadratic or similar. 6. **Average rate of change:** For example, between speeds 10 and 20: $$\text{Average rate of change} = \frac{43 - 16}{20 - 10} = \frac{27}{10} = 2.7$$ This means for each 1 mi/hr increase in speed from 10 to 20, stopping distance increases by 2.7 ft on average. 7. **Summary:** Independent variable: Speed (mi/hr). Dependent variable: Stopping Distance (ft). Domain: $\{10, 20, 30, 40, 50, 60, 70\}$. Range: $\{16, 43, 74, 117, 169, 223, 307\}$. The function shows increasing stopping distance with increasing speed, with a nonlinear growth pattern.