1. **Problem 2:** Determine approximately how long the weight is higher than 4 m based on the graph of height $h$ versus time $t$. 2. From the graph description, the weight starts above 4 m at $t=0$, rises to a peak above 6 m near $t=1$, then dips below 4 m near $t=3$, rises back to 4 m at about $t=6$, then dips below 4 m again. 3. The weight is higher than 4 m from $t=0$ to approximately $t=3$, and again from about $t=5$ to $t=6$. 4. Calculate the total time higher than 4 m: $$\text{Time} = (3 - 0) + (6 - 5) = 3 + 1 = 4 \text{ seconds}$$ --- 5. **Problem 3:** Sketch the graph of the combined function $y = f(g(x))$ where $f(x) = 2^x$ and $g(x) = x - 1$. 6. The combined function is: $$y = f(g(x)) = 2^{x-1}$$ 7. This is an exponential function shifted to the right by 1 unit compared to $2^x$. 8. Key points: - At $x=1$, $y=2^{1-1} = 2^0 = 1$ - At $x=0$, $y=2^{-1} = \frac{1}{2}$ 9. The graph passes through $(1,1)$ and approaches zero as $x \to -\infty$, increasing exponentially as $x$ increases. --- **Final answers:** - The weight is higher than 4 m for approximately 4 seconds. - The combined function is $y = 2^{x-1}$, an exponential curve shifted right by 1.