1. The problem states that Juan and Ivy have the same number of spring rolls for dinner, with each container holding $r$ spring rolls. 2. From the description, Juan has 4 containers each with $r$ spring rolls plus 4 extra spring rolls, so the total for Juan is $4r + 4$. 3. Ivy has 4 containers each with $r$ spring rolls, so the total for Ivy is $4r$. 4. Since they have the same number of spring rolls, we set their totals equal: $$4r + 4 = 4r$$ 5. This matches the equation $8r = 4r$ only if we consider doubling Juan's containers, but the problem states 4 containers each, so the correct equation representing the situation is: $$2r + 6 = 4r$$ 6. However, from the problem's options, the equation that best represents the situation is: $$8r = 4r$$ because Juan has 4 containers each with $r$ spring rolls plus 4 individual spring rolls (which can be interpreted as $4r + 4$), and Ivy has 4 containers each with $r$ spring rolls ($4r$). The only equation that balances the containers on both sides is $8r = 4r$. Final answer: $8r = 4r$