1. The problem states: $\sqrt{2401} = 11$ and we need to verify if this is true.\n\n2. The square root of a number $x$ is a value $y$ such that $y^2 = x$. Here, $y = 11$.\n\n3. Calculate $11^2$: $$11^2 = 11 \times 11 = 121$$\n\n4. Compare $121$ with $2401$: $121 \neq 2401$, so $\sqrt{2401} \neq 11$.\n\n5. Let's find the correct square root of 2401 by trial or prime factorization. Since $2401 = 49^2$, and $49 = 7^2$, indeed: $$49^2 = 2401$$\n\n6. Therefore, $\sqrt{2401} = 49$, not 11.\n\nFinal answer: \boxed{49}