Subjects algebra

Sqrt 250

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1. The problem is to find the square root of 250. 2. Start by expressing 250 as a product of its prime factors or perfect squares: $$250 = 25 \times 10$$. 3. Since 25 is a perfect square, we can write: $$\sqrt{250} = \sqrt{25 \times 10}$$. 4. Use the property of square roots: $$\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$$. 5. Therefore, $$\sqrt{250} = \sqrt{25} \times \sqrt{10} = 5 \times \sqrt{10}$$. 6. The simplified form of the square root of 250 is $$5\sqrt{10}$$. 7. If you want a decimal approximation, $$\sqrt{10} \approx 3.162$$, so $$5 \times 3.162 = 15.81$$ approximately. Final answer: $$\sqrt{250} = 5\sqrt{10} \approx 15.81$$.