1. The problem asks us to find which point on the number line corresponds to $\sqrt{26}$. 2. First, calculate $\sqrt{26}$. Since $25$ is a perfect square and $\sqrt{25} = 5$, and $26$ is just a bit larger than $25$, $\sqrt{26}$ will be slightly more than $5$. 3. To estimate $\sqrt{26}$, note that: $$5^2 = 25 \quad \text{and} \quad 6^2 = 36$$ Since $26$ is closer to $25$ than to $36$, $\sqrt{26}$ is closer to $5$ than to $6$. 4. Using a calculator or approximation: $$\sqrt{26} \approx 5.099$$ 5. Now, compare this value to the positions of the points on the number line: - Point A is around $5.1$ - Point B is around $5.3$ - Point C is around $5.55$ - Point D is around $5.8$ 6. Since $5.099$ is closest to $5.1$, the point that shows the position of $\sqrt{26}$ is Point A. **Final answer:** Point A corresponds to $\sqrt{26}$.