1. The problem is to simplify the square root of 98, written as $\sqrt{98}$.\n\n2. Recall the rule for simplifying square roots: $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$. We look for perfect square factors of 98.\n\n3. Factor 98 into $49 \times 2$ because 49 is a perfect square.\n\n4. Apply the rule: $$\sqrt{98} = \sqrt{49 \times 2} = \sqrt{49} \times \sqrt{2}$$\n\n5. Since $\sqrt{49} = 7$, we have: $$7 \times \sqrt{2}$$\n\n6. Therefore, the simplified form of $\sqrt{98}$ is $7\sqrt{2}$.