1. **State the problem:** We need to translate the equation "square root of (x + 4) + square root of (x + 2) = 6" into a mathematical equation and then solve for $x$.
2. **Write the equation:** The square root of a number $a$ is written as $\sqrt{a}$. So the equation becomes:
$$\sqrt{x+4} + \sqrt{x+2} = 6$$
3. **Isolate one square root:** To solve, isolate one of the square roots. Let's isolate $\sqrt{x+4}$:
$$\sqrt{x+4} = 6 - \sqrt{x+2}$$
4. **Square both sides:** Squaring both sides removes the square root on the left:
$$\left(\sqrt{x+4}\right)^2 = \left(6 - \sqrt{x+2}\right)^2$$
$$x + 4 = 36 - 12\sqrt{x+2} + (x + 2)$$
5. **Simplify:** Combine like terms:
$$x + 4 = 36 + x + 2 - 12\sqrt{x+2}$$
$$x + 4 = x + 38 - 12\sqrt{x+2}$$
6. **Subtract $x$ from both sides:**
$$4 = 38 - 12\sqrt{x+2}$$
7. **Isolate the square root term:**
$$-34 = -12\sqrt{x+2}$$
$$\sqrt{x+2} = \frac{34}{12} = \frac{17}{6}$$
8. **Square both sides again:**
$$x + 2 = \left(\frac{17}{6}\right)^2 = \frac{289}{36}$$
9. **Solve for $x$:**
$$x = \frac{289}{36} - 2 = \frac{289}{36} - \frac{72}{36} = \frac{217}{36}$$
10. **Check the solution:** Substitute $x = \frac{217}{36}$ back into the original equation:
$$\sqrt{\frac{217}{36} + 4} + \sqrt{\frac{217}{36} + 2} = \sqrt{\frac{217}{36} + \frac{144}{36}} + \sqrt{\frac{217}{36} + \frac{72}{36}} = \sqrt{\frac{361}{36}} + \sqrt{\frac{289}{36}} = \frac{19}{6} + \frac{17}{6} = 6$$
The solution satisfies the original equation.
**Final answer:**
$$x = \frac{217}{36}$$
Sqrt Equation E66Ea3
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