1. The problem is to analyze the function $f(x) = \sqrt{x + 2}$ and understand its behavior. 2. The formula used is the square root function, which is defined only for values where the expression inside the root is non-negative. That means: $$x + 2 \geq 0$$ 3. Solve the inequality: $$x \geq -2$$ This tells us the domain of $f(x)$ is all $x$ values greater than or equal to $-2$. 4. To find values of $f(x)$ for the table, substitute values of $x$ starting from $-2$ and increasing: - For $x = -2$, $f(-2) = \sqrt{-2 + 2} = \sqrt{0} = 0$ - For $x = -1$, $f(-1) = \sqrt{-1 + 2} = \sqrt{1} = 1$ - For $x = 0$, $f(0) = \sqrt{0 + 2} = \sqrt{2}$ - For $x = 2$, $f(2) = \sqrt{2 + 2} = \sqrt{4} = 2$ 5. The function increases as $x$ increases because the square root function is increasing. 6. The graph will start at the point $(-2, 0)$ and curve upwards to the right. Final answer: The domain of $f(x)$ is $x \geq -2$, and the function values increase as $x$ increases starting from $0$ at $x = -2$.