1. The problem is to identify the graph of the function $$f(x) = \sqrt{x - 4} + 3$$. 2. The general form of a square root function is $$f(x) = \sqrt{x - h} + k$$, where $(h, k)$ is the starting point (vertex) of the graph. 3. For $$f(x) = \sqrt{x - 4} + 3$$, the graph starts at $$x = 4$$ because the expression inside the square root must be non-negative: $$x - 4 \geq 0 \Rightarrow x \geq 4$$. 4. The starting point (vertex) is therefore at $$(4, 3)$$. 5. The graph moves upward and to the right from this point because the square root function increases as $x$ increases. 6. Comparing the given graph descriptions: - Bottom-left graph starts near $$(1, 3)$$, which does not match the vertex. - Center graph starts near $$(1, 3)$$, also does not match. - Bottom-right graph starts near $$(4, 3)$$, which matches the vertex. 7. Therefore, the correct graph is the bottom-right graph. Final answer: The graph of $$f(x) = \sqrt{x - 4} + 3$$ is the bottom-right graph starting at $$(4, 3)$$ and moving upward and to the right.