1. The problem is to identify the graph of the equation $$y - 3 = \sqrt{x - 2}$$. 2. This equation can be rewritten as $$y = 3 + \sqrt{x - 2}$$. 3. The square root function $$\sqrt{x - 2}$$ is defined only for $$x \geq 2$$ because the expression inside the square root must be non-negative. 4. When $$x = 2$$, $$y = 3 + \sqrt{0} = 3$$, so the graph starts at the point $$(2, 3)$$. 5. As $$x$$ increases beyond 2, $$\sqrt{x - 2}$$ increases, so $$y$$ increases, making the graph rise to the right. 6. The graph is a square root curve shifted right by 2 units and up by 3 units. 7. Comparing with the descriptions: - The first graph starts near $$(-2, 1)$$, which does not match our starting point. - The second graph starts near $$(2, 3)$$ and increases to the right, matching our graph. - The third graph starts near $$(2, 2)$$, which does not match. Final answer: The equation corresponds to the second graph (bottom-center).