Subjects algebra

Sqrt Scientific

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1. **State the problem:** We need to find the value of $$\sqrt{2.307197196 \times 10^{-28}}$$. 2. **Recall the property of square roots:** The square root of a product is the product of the square roots: $$\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$$. 3. **Apply this property:** $$\sqrt{2.307197196 \times 10^{-28}} = \sqrt{2.307197196} \times \sqrt{10^{-28}}$$. 4. **Calculate each part:** - Calculate $$\sqrt{2.307197196}$$. Using a calculator or approximation, this is approximately $$1.519$$. - Calculate $$\sqrt{10^{-28}}$$. Since $$\sqrt{10^{n}} = 10^{n/2}$$, we have: $$\sqrt{10^{-28}} = 10^{-28/2} = 10^{-14}$$. 5. **Combine the results:** $$1.519 \times 10^{-14}$$. 6. **Final answer:** $$\sqrt{2.307197196 \times 10^{-28}} \approx 1.519 \times 10^{-14}$$. This means the square root of the given number is approximately $$1.519 \times 10^{-14}$$.