1. The problem is to understand and graph the function $f(x) = \sqrt{x + 2}$. 2. This function is a square root function shifted horizontally. The general form is $f(x) = \sqrt{x - h}$, where $h$ is the horizontal shift. 3. Here, $f(x) = \sqrt{x + 2}$ can be rewritten as $f(x) = \sqrt{x - (-2)}$, so the graph is shifted 2 units to the left. 4. The domain of $f(x)$ is all $x$ such that the expression inside the square root is non-negative: $$x + 2 \geq 0 \implies x \geq -2.$$ So the graph starts at $x = -2$. 5. At $x = -2$, $f(-2) = \sqrt{-2 + 2} = \sqrt{0} = 0$, so the point $(-2, 0)$ is on the graph. 6. For values of $x > -2$, $f(x)$ increases as the square root of $x + 2$. 7. The graph shape is a curve starting at $(-2, 0)$ and increasing slowly to the right. Final answer: The function $f(x) = \sqrt{x + 2}$ is a square root curve shifted 2 units left, starting at $(-2, 0)$ and increasing to the right.