1. **State the problem:** We are given the function $y = 3 - \sqrt{x}$ and want to understand its behavior. 2. **Recall the formula and domain:** The function involves a square root, so the domain is $x \geq 0$ because the square root of a negative number is not a real number. 3. **Analyze the function:** The function subtracts the square root of $x$ from 3. As $x$ increases, $\sqrt{x}$ increases, so $y$ decreases. 4. **Find intercepts:** - **y-intercept:** Set $x=0$, then $y=3-\sqrt{0}=3-0=3$. - **x-intercept:** Set $y=0$, then $0=3-\sqrt{x}$ which gives $\sqrt{x}=3$, so $x=9$. 5. **Summary:** The function starts at $(0,3)$ and decreases to 0 at $x=9$, then continues decreasing for larger $x$ values. Final answer: The function $y=3-\sqrt{x}$ has domain $x \geq 0$, y-intercept at $(0,3)$, and x-intercept at $(9,0)$.