1. The problem asks if $\sqrt{3} + \sqrt{2} = \sqrt{5}$ is true. 2. Recall the property of square roots: $\sqrt{a} + \sqrt{b} \neq \sqrt{a+b}$ in general. 3. To check, calculate each side approximately: - $\sqrt{3} \approx 1.732$ - $\sqrt{2} \approx 1.414$ - Sum: $1.732 + 1.414 = 3.146$ - $\sqrt{5} \approx 2.236$ 4. Since $3.146 \neq 2.236$, the equation $\sqrt{3} + \sqrt{2} = \sqrt{5}$ is false. 5. Important rule: $\sqrt{a} + \sqrt{b} \neq \sqrt{a+b}$, but $\sqrt{a} \times \sqrt{b} = \sqrt{ab}$. 6. Therefore, $\sqrt{3} + \sqrt{2} \neq \sqrt{5}$.