1. **Problem Statement:** Simplify the expression $$\left(4 \sqrt{5} + 3 \right)^2$$.
2. **Formula Used:** The square of a binomial $$ (a + b)^2 = a^2 + 2ab + b^2 $$.
3. **Identify terms:** Here, $$a = 4 \sqrt{5}$$ and $$b = 3$$.
4. **Calculate each term:**
- $$a^2 = (4 \sqrt{5})^2 = 4^2 \times (\sqrt{5})^2 = 16 \times 5 = 80$$
- $$2ab = 2 \times 4 \sqrt{5} \times 3 = 24 \sqrt{5}$$
- $$b^2 = 3^2 = 9$$
5. **Combine all terms:**
$$80 + 24 \sqrt{5} + 9 = 89 + 24 \sqrt{5}$$
6. **Final answer:**
$$\left(4 \sqrt{5} + 3 \right)^2 = 89 + 24 \sqrt{5}$$
This expression is simplified and cannot be reduced further because $$\sqrt{5}$$ is irrational.
Square Bracket Surds
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