1. The problem asks what output will be displayed if the user inputs 0 for the area of a square. 2. The pseudocode is: area = input "Enter the area of the square:" if area < 0 display "error" else perimeter = 4*sqrt(area) display perimeter 3. Important rules: - The area of a square cannot be negative, so if area < 0, the program displays "error". - The perimeter of a square is given by $P = 4 \times \text{side}$. - Since area $A = \text{side}^2$, the side length is $\sqrt{A}$. - Therefore, perimeter $P = 4 \times \sqrt{A}$. 4. Given the input area = 0: - Check if area < 0: $0 < 0$ is false, so no error. - Calculate perimeter: $$P = 4 \times \sqrt{0} = 4 \times 0 = 0$$ 5. The program will display the perimeter, which is 0. Final answer: 0