1. The problem is to find the square root of 49. 2. The square root of a number $x$ is a value $y$ such that $$y^2 = x$$. 3. For positive numbers, the principal square root is the positive value that satisfies this. 4. Calculate the square root of 49: $$\sqrt{49} = y$$ 5. Since $$7^2 = 49$$, we have: $$\sqrt{49} = 7$$ 6. Therefore, the square root of 49 is 7.