1. The problem is to find the square root of a number greater than 150. 2. The square root of a number $x$ is a value $y$ such that $y^2 = x$. 3. Since the problem states "over 150," let's find the square root of 150 as a reference point. 4. Calculate $\sqrt{150}$. 5. Simplify $\sqrt{150} = \sqrt{25 \times 6} = \sqrt{25} \times \sqrt{6} = 5\sqrt{6}$. 6. The approximate decimal value is $5 \times 2.449 = 12.245$. 7. Therefore, the square root of any number over 150 will be greater than approximately 12.245. 8. For example, $\sqrt{160} \approx 12.649$. 9. So, the square root over 150 is any value greater than $12.245$.