Subjects algebra

Squares Order 25Ffe1

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1. **State the problem:** We need to select all the squares from the given expressions and order them from least to greatest. 2. **Identify squares:** A square is a number raised to the power 2, or a perfect square number. Among the expressions, the only clear perfect square is $2!$ because $2! = 2 \times 1 = 2$, which is not a perfect square. The summation $\sum_{i=1}^2 i = 1 + 2 = 3$ is not a square. The other expressions are not perfect squares either. 3. **Check if any expression is a perfect square:** - $\sqrt{11}$ is approximately 3.316, not a square. - $\log_4(13)$ is about 1.85, not a square. - $\frac{3\pi}{6} = \frac{\pi}{2} \approx 1.5708$, not a square. - $\frac{10}{14} = \frac{5}{7} \approx 0.714$, not a square. - $\int_2^7 x \, dx = \left[ \frac{x^2}{2} \right]_2^7 = \frac{7^2}{2} - \frac{2^2}{2} = \frac{49}{2} - 2 = 24.5 - 2 = 22.5$, not a square. - $e^5$ is about 148.413, not a square. - $\sum_{i=1}^2 i = 3$, not a square. - $\infty$ is not a number. - $2! = 2$, not a square. 4. **Conclusion:** None of the given expressions are perfect squares. 5. **If the question means to select the squares of these expressions (i.e., square each), then order them:** - Square each: - $(\sqrt{11})^2 = 11$ - $(\log_4(13))^2 \approx (1.85)^2 = 3.4225$ - $(\frac{3\pi}{6})^2 = (\frac{\pi}{2})^2 = \frac{\pi^2}{4} \approx 2.4674$ - $(\frac{10}{14})^2 = (\frac{5}{7})^2 = \frac{25}{49} \approx 0.5102$ - $(\int_2^7 x \, dx)^2 = (22.5)^2 = 506.25$ - $(e^5)^2 = e^{10} \approx 22026.4658$ - $(\sum_{i=1}^2 i)^2 = 3^2 = 9$ - $(2!)^2 = 2^2 = 4$ 6. **Order these squares from least to greatest:** $$0.5102, 2.4674, 3.4225, 4, 9, 11, 506.25, 22026.4658$$ 7. **Match back to original expressions:** - $\frac{10}{14}$ - $\frac{3\pi}{6}$ - $\log_4(13)$ - $2!$ - $\sum_{i=1}^2 i$ - $\sqrt{11}$ - $\int_2^7 x \, dx$ - $e^5$ **Final answer:** The squares of the expressions in order from least to greatest are: $$\frac{10}{14}, \frac{3\pi}{6}, \log_4(13), 2!, \sum_{i=1}^2 i, \sqrt{11}, \int_2^7 x \, dx, e^5$$